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0.5x^2-3x+1.25=0
a = 0.5; b = -3; c = +1.25;
Δ = b2-4ac
Δ = -32-4·0.5·1.25
Δ = 6.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{6.5}}{2*0.5}=\frac{3-\sqrt{6.5}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{6.5}}{2*0.5}=\frac{3+\sqrt{6.5}}{1} $
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